![Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/fig_52a4944619864405640501.png "Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com")
Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com
The value of a and b such that the function f(x) {:{(-2 sin x", "-pile x le -pi/2 ),(a sin x+b " ," -pi/2 lt x lt pi/2 ),(cos x", " pi/2
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%2B3\tan(%CF%80-x)=0&line2=\mathrm{Solution:\:}x=\frac{%CF%80}{6}%2B2%CF%80n,x=\frac{5%CF%80}{6}%2B2%CF%80n "2sin(x+pi/2)+3tan(pi-x)=0")
2sin(x+pi/2)+3tan(pi-x)=0
![The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$](https://www.vedantu.com/question-sets/81a6a607-6f3b-42d1-bdc3-6feedb76da524897162654211039244.png "The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$")
The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$
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Let f(x)={-2sinx for -pi<=x <=-pi/2 a sin x+ b for - pi/2 < x < pi/2.cos x for pi/2 <= x <= pi if f is continuous on [-pi, pi).then find the
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Let f(x) = sin (π/6 sin (π/2 sin x)) for all ∈ R and g (x) =π/2 sin x for all x ∈ R. Let (fog)(x) denote f(g(x) and (gof) (x)denote g(f(x)). -
![lim(x->pi/2) [sinx] is](https://d10lpgp6xz60nq.cloudfront.net/ss/web/81305.jpg "lim(x->pi/2) [sinx] is")
lim(x->pi/2) [sinx] is
