![complex analysis - Fourier series of function $f(x)=0$ if $-\pi<x<0$ and $f( x)=\sin(x)$ if $0<x<\pi$ - Mathematics Stack Exchange complex analysis - Fourier series of function $f(x)=0$ if $-\pi<x<0$ and $f( x)=\sin(x)$ if $0<x<\pi$ - Mathematics Stack Exchange](https://i.stack.imgur.com/AFTsT.jpg)
complex analysis - Fourier series of function $f(x)=0$ if $-\pi<x<0$ and $f( x)=\sin(x)$ if $0<x<\pi$ - Mathematics Stack Exchange
![If `f(x) {-x-pi/2,xle-pi/2 and -cosx,-pi/2 lt xle0 and x-1,0 lt x le1 and lnx,x gt 1` then- - YouTube If `f(x) {-x-pi/2,xle-pi/2 and -cosx,-pi/2 lt xle0 and x-1,0 lt x le1 and lnx,x gt 1` then- - YouTube](https://i.ytimg.com/vi/TZiMWErl6c0/maxresdefault.jpg)
If `f(x) {-x-pi/2,xle-pi/2 and -cosx,-pi/2 lt xle0 and x-1,0 lt x le1 and lnx,x gt 1` then- - YouTube
![Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is](https://haygot.s3.amazonaws.com/questions/1553048_121246_ans_1a21ea3929b041efa356547e6dbebd40.jpg)
Consider the function f(x) = x sin pi/x, for x>0 0, for x = 0 . Then, the number of points in (0,1) where the derivative f'(x) vanishes is
![If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube](https://i.ytimg.com/vi/Ibx1ycLyoGE/maxresdefault.jpg)
If `f(x) = cos [pi]x + cos [pi x]`, where `[y]` is the greatest integer function of y then `f - YouTube
![Obtain the Fourier series for the function f(x) = x ^ 2 -Pai < x < Pai - MATHEMATICS-3 question answer collection Obtain the Fourier series for the function f(x) = x ^ 2 -Pai < x < Pai - MATHEMATICS-3 question answer collection](https://www.rgpvonline.com/answer/mathematics-3/img/2-1.jpg)
Obtain the Fourier series for the function f(x) = x ^ 2 -Pai < x < Pai - MATHEMATICS-3 question answer collection
![Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange](https://i.stack.imgur.com/lAKpd.jpg)
Use Fourier series of $f(x)=x(\pi-|x|)$ in $(-\pi,\pi)$ to compute the series $\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{(2n-1)^3}.$ - Mathematics Stack Exchange
![For tha function `f(x)=(pi-x)(cosx)/(|sinx|); x!=pi and f(pi)=1,` which of the following state - YouTube For tha function `f(x)=(pi-x)(cosx)/(|sinx|); x!=pi and f(pi)=1,` which of the following state - YouTube](https://i.ytimg.com/vi/DdxaRwiZNvY/maxresdefault.jpg)